(4x/x+3)-(12/x-3)=(4x^2+36/x^2-9)

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Solution for (4x/x+3)-(12/x-3)=(4x^2+36/x^2-9) equation: 



(4x/x+3)-(12/x-3)=(4x^2+36/x^2-9)

We move all terms to the left:

(4x/x+3)-(12/x-3)-((4x^2+36/x^2-9))=0



Domain of the equation: x+3)!=0

x∈R





Domain of the equation: x-3)!=0

x∈R





Domain of the equation: x^2-9))!=0

x∈R



We get rid of parentheses

4x/x-12/x-((4x^2+36/x^2-9))+3+3=0

We calculate fractions

We do not support expression: x^3

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